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For light going from a medium of refractive index n to air, the critical angle i_c is given by:

Asin i_c = n
Bsin i_c = 1/n
Ccos i_c = n
Dtan i_c = 1/n
Answer & Solution
Correct answer: B. sin i_c = 1/n
At the critical angle, r = 90°. **Snell's law:** **n × sin i_c = 1 × sin 90° = 1 → sin i_c = 1/n**. For water (n = 1.33): i_c ≈ 48.75°. For diamond (n = 2.42): i_c ≈ 24.4° (small i_c → strong TIR → diamond sparkle).
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