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Solubility product (K_sp) of a sparingly soluble salt AgCl is given by
A[Ag⁺]²[Cl⁻]
B[Ag⁺][Cl⁻]²
C[AgCl]/[Ag⁺]
D[Ag⁺][Cl⁻]
Answer & Solution
Correct answer: D. [Ag⁺][Cl⁻]
1. For AgCl(s) ⇌ Ag⁺(aq) + Cl⁻(aq) the equilibrium constant excludes the pure solid.
2. Hence K_sp = [Ag⁺][Cl⁻].
3. K_sp is the product of equilibrium ion concentrations raised to their stoichiometric powers.
_Source: Maharashtra Balbharati Std XII Chemistry, Ch 3 "Ionic Equilibria" §3.10_
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