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pH of 0.01 M HCl (a strong acid) at 25 °C is
A1
B12
C2
D0.01
Answer & Solution
Correct answer: C. 2
1. HCl fully ionises so [H⁺] = 0.01 M = 10⁻² M.
2. pH = −log [H⁺] = −log 10⁻².
3. pH = 2.
_Source: Maharashtra Balbharati Std XII Chemistry, Ch 3 "Ionic Equilibria" §3.6_
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