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What is the pH of a 1 x 10^-4 molar solution of sodium hydroxide, a strong base, at 25 degrees Celsius?
A4
B10
C7
D14
Answer & Solution
Correct answer: B. 10
1. NaOH fully dissociates, so [OH-] = 1 x 10^-4 mol per litre.
2. pOH = -log10[OH-] = -log10(10^-4) = 4.
3. Use the relation pH + pOH = 14, so pH = 14 - 4 = 10.
4. Therefore pH = 10; the value 4 is the pOH, not the pH, a common trap for a basic solution.
_Source: Samacheer Kalvi (TN SCERT) Class 10 Science, Unit 10 Types of Chemical Reactions "Problems", p.157_
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