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Tamil Nadu SSLC (Class 10) — free MCQ practice

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The notes calculate $\lambda_m^c$ using $\lambda_m^c = \dfrac{0.04 \times 1000}{0.1}$. What value is obtained?

  1. 40
  2. 400
  3. 4000
  4. 4
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Correct answer: B. 400

Compute $\lambda_m^c = \dfrac{0.04 \times 1000}{0.1} = \dfrac{40}{0.1} = 400$.

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From the expression shown, $\lambda_m^{\infty}(HA) = 400 + 500 - 50$, the limiting molar conductivity of $HA$ is

  1. 850
  2. 950
  3. 400
  4. 50
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Correct answer: A. 850

Direct evaluation gives $400 + 500 - 50 = 850$. **Therefore, $\lambda_m^{\infty}(HA) = 850$.**

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From a standard deck of 52 playing cards, what is the probability of drawing a heart?

  1. $\dfrac{1}{2}$
  2. $\dfrac{1}{4}$
  3. $\dfrac{13}{52}$
  4. Both B and C are correct
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Correct answer: D. Both B and C are correct

A standard deck has 13 hearts out of 52 cards. So the probability is $\dfrac{13}{52}=\dfrac14$. **Hence both options B and C represent the same correct value, so D is the intended correct choice.**

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