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Using electronegativity values F = 4.0 and Na = 0.9 (approx 1.0), the Na-F bond is best described as:

AMore ionic in character
BMore covalent in character
CPurely covalent in character
DA non-polar bond
Answer & Solution
Correct answer: A. More ionic in character
1. Electronegativity difference $= 4.0 - 1.0 = 3.0$. 2. The rule: difference greater than 1.7 means a more ionic bond. 3. Since 3.0 is well above 1.7, the Na-F bond is more ionic. A difference below 1.7 would have made it more covalent, but 3.0 is far higher. _Source: Samacheer Kalvi (TN SCERT) Class 10 Science, Unit 8 Periodic Classification of Elements "Electronegativity", p.118_
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