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Complete the displacement reaction: CuSO$_4$(aq) + Fe(s) $\longrightarrow$ ___ + ___
AFe$_2$(SO$_4$)$_3$(aq) + Cu(s)
BFeSO$_4$(aq) + Cu(s)
CFeS(aq) + CuO(s)
DFeSO$_4$(aq) + CuO(s)
Answer & Solution
Correct answer: B. FeSO$_4$(aq) + Cu(s)
1. Iron is more reactive than copper, so Fe displaces Cu from copper sulphate.
2. Fe takes the sulphate to form ferrous sulphate FeSO$_4$, and copper metal Cu is set free.
3. The product is therefore FeSO$_4$(aq) + Cu(s).
4. The FeS option invents a sulphide, the Fe$_2$(SO$_4$)$_3$ option wrongly gives ferric salt from a simple displacement, and the CuO option wrongly forms CuO instead of free Cu.
_Source: Balbharati (Maharashtra Board) Class 10 Science & Technology, Ch 3 "Chemical Reactions and Equations", p.47_
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