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A hydraulic press has small piston area 0.01 m^2 and large piston area 0.2 m^2. A force of 50 N on the small piston gives a force on the large piston of
A100 N only
B500 N only
C1000 N
D10 N only
Answer & Solution
Correct answer: C. 1000 N
1. Pressure on small piston = 50/0.01 = 5000 Pa.
2. By Pascal's law the same pressure acts on the large piston.
3. Force = pressure * area = 5000 * 0.2.
4. = 1000 N.
_Source: Selina Concise Physics Class 9, Ch 4 Pressure in Fluids and Atmospheric Pressure (Mistral OCR'd PDF), section on Pascal's law applications_
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