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Two liquids X and Y have densities 800 and 1200 kg/m^3. At depth 2 m the pressures are P_X and P_Y. The ratio P_X : P_Y is
A3 : 2
B2 : 3
C1 : 1
D4 : 9
Answer & Solution
Correct answer: B. 2 : 3
1. P = h * rho * g with same h and g.
2. P_X / P_Y = rho_X / rho_Y = 800/1200.
3. = 2/3.
4. So P_X : P_Y = 2 : 3.
_Source: Selina Concise Physics Class 9, Ch 4 Pressure in Fluids and Atmospheric Pressure (Mistral OCR'd PDF), section on density and pressure_
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