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Pressure at the bottom of a 4 m deep water column (rho = 1000 kg/m^3, g = 10 m/s^2) is
A100 Pa only
B4000 Pa only
C400 Pa only
D40000 Pa
Answer & Solution
Correct answer: D. 40000 Pa
1. Use P = h * rho * g.
2. P = 4 * 1000 * 10.
3. = 40000 Pa.
4. So the pressure is 40000 Pa.
_Source: Selina Concise Physics Class 9, Ch 4 Pressure in Fluids and Atmospheric Pressure (Mistral OCR'd PDF), section on numerical examples_
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