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How many oxygen atoms are present in 49 g of H2SO4 (molar mass 98)?
A3.011 * 10^23
B1.204 * 10^24
C6.022 * 10^23
D2.408 * 10^24
Answer & Solution
Correct answer: A. 3.011 * 10^23
1. Moles of H2SO4 = 49 / 98 = 0.5 mole.
2. Each H2SO4 has 4 oxygen atoms.
3. Moles of O = 0.5 * 4 = 2 moles.
4. Atoms = 2 * 6.022 * 10^23 = 1.204 * 10^24.
5. So 49 g of H2SO4 has 1.204 * 10^24 oxygen atoms.
_Source: Selina Concise Chemistry ICSE Class 10, Ch 5 'Mole Concept and Stoichiometry'_
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