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The volume of 7 g of nitrogen (N2, molar mass 28) at STP is:
A5.6 L
B22.4 L
C11.2 L
D2.8 L
Answer & Solution
Correct answer: A. 5.6 L
1. Moles of N2 = 7 / 28 = 0.25 mole.
2. Volume at STP = moles * 22.4.
3. = 0.25 * 22.4 = 5.6 litres.
4. So 7 g of N2 occupies 5.6 L at STP.
_Source: Selina Concise Chemistry ICSE Class 10, Ch 5 'Mole Concept and Stoichiometry'_
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