For a zero-order reaction, if the initial concentration is doubled, the half-life:
ARemains the same
BHalves
CBecomes four times
DDoubles
Answer & Solution
Correct answer: D. Doubles
Zero-order **t_(1/2) = [R]₀/(2k)** — directly proportional to initial concentration. Doubling [R]₀ → t_(1/2) doubles. (Contrast first-order, where t_(1/2) is independent of [R]₀.)
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