On a plot of ln k versus 1/T (Arrhenius plot), what is the slope?
A+E_a/(2.303 R)
Bln A
C−E_a/R
D+E_a/R
Answer & Solution
Correct answer: C. −E_a/R
**Taking ln of Arrhenius:** ln k = ln A − E_a/RT.
So **ln k vs 1/T → slope = −E_a/R, intercept = ln A**.
This is the standard graphical method to find E_a experimentally.
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