For a first-order reaction, if the initial concentration of N₂O₅ is 1.24 × 10⁻² mol L⁻¹ and after 60 min it is 0.20 × 10⁻² mol L⁻¹, the rate constant k is approximately:
A6.2 min⁻¹
B0.0030 min⁻¹
C0.030 min⁻¹
D0.30 min⁻¹
Answer & Solution
Correct answer: C. 0.030 min⁻¹
k = (2.303/t) log([R]₀/[R]) = (2.303/60) log(1.24/0.20) = (2.303/60) × log(6.2) = (2.303/60) × 0.7924 ≈ **0.030 min⁻¹**.
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