Start learning →

The relation between cell EMF and Gibbs free-energy change is:

AΔG = +nFE_cell
BΔG = nF/E_cell
CΔG = −nFE_cell
DΔG = E_cell/nF
Answer & Solution
Correct answer: C. ΔG = −nFE_cell
**ΔG = −nFE_cell**. A positive E_cell (spontaneous galvanic) corresponds to negative ΔG (spontaneous reaction). Watch the sign — this also explains why doubling the cell reaction doubles ΔG but does NOT change E_cell (intensive).
Practise this question with Quill — NEET UG →

Keep practising Unit 9B1: Electrochemical Cells and Standard Potentials

Browse all Unit 9B1: Electrochemical Cells and Standard Potentials questions for NEET UG, or explore more Chemistry topics.

Start a Unit 9B1: Electrochemical Cells and Standard Potentials lesson →