The de-Broglie wavelength associated with a particle of mass $10^{-6}$ kg with a velocity of $10 \, ms^{-1}$ is:

Using de Broglie relation, $\lambda=\dfrac{h}{mv}$. Substituting $h=6.626\times10^{-34}\,\text{J s}$, $m=10^{-6}\,\text{kg}$, and $v=10\,\text{m s}^{-1}$ gives $\lambda=\dfrac{6.626\times10^{-34}}{10^{-5}}=6.626\times10^{-29}\,\text{m}$.