alleryFor the cell Cu(s) + 2Ag⁺ → Cu²⁺ + 2Ag, E°_cell = +0.46 V at 298 K. The equilibrium constant K_c is approximately:
A1.0 × 10²
B3.92 × 10¹⁵
C0.46
D2.0 × 10³⁷
Answer & Solution
Correct answer: B. 3.92 × 10¹⁵
log K_c = (n × E°)/0.059 = (2 × 0.46)/0.059 ≈ 15.6. So **K_c ≈ 10¹⁵·⁶ ≈ 3.92 × 10¹⁵**.
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