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Per NCERT §3.7.1(e) + Table 3.8, ELECTRONEGATIVITY on the Pauling scale assigns which value to FLUORINE — and what is its trend across a period?
AF = 1.0; decreases across
BF = 7.0; increases down
CF = 4.0; electronegativity INCREASES across a period (left → right)
DF = 2.5; constant
Answer & Solution
Correct answer: C. F = 4.0; electronegativity INCREASES across a period (left → right)
Per NCERT §3.7.1(e), Pauling 1922: F = 4.0 (max). Across a period EN ↑ (atomic radius ↓). Down a group EN ↓.
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