alleryStart learning →Compare sums of ordered pairs: real numbers satisfy a<b and c<d. What must follow?
Aa+c<b+d
Ba+c≤b−d
Ca+c>b+d
Da+c=b+d
Answer & Solution
Correct answer: A. a+c<b+d
Adding c to a<b gives a+c<b+c, and adding b to c<d gives b+c<b+d. Together these imply a+c<b+d.
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