alleryStart learning →Expand the negative bracket in 3−2(x−1)≥9 and solve for real x.
Ax≥−4
Bx≤−2
Cx≥−2
Dx≤−4
Answer & Solution
Correct answer: B. x≤−2
Expanding gives 5−2x≥9, so −2x≥4. Division by −2 reverses the sign and gives x≤−2.
Keep practising Linear Inequalities
Browse all Linear Inequalities questions for ICSE Class 8, or explore more Mathematics topics.
Related questions
A portion of the number line runs from 2 to 5, including 2 but excluding 5. Which conditioA rectangle is 8 cm long and w cm wide, with w>0. If its perimeter is at most 30 cm, what Two test scores are 62 and 48. What is the least third whole-number score, out of 100, forAn order costs ₹20 plus ₹7 per notebook. No other charges. With ₹60, what is the most noteEach completed task earns 3 points. What is the fewest tasks needed to earn at least 20 poClear numerical denominators to solve (x−1)/2≤(x+3)/3 for real x.Collect variable terms from both sides of 4x+3<6x+7. Which restriction on real x results?Account for the subtracted variable in 5−x≥8. Which restriction on real x follows?