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Clear numerical denominators to solve (x−1)/2≤(x+3)/3 for real x.

Ax≤3
Bx≥9
Cx≥3
Dx≤9
Answer & Solution
Correct answer: D. x≤9
Multiplying by positive 6 gives 3(x−1)≤2(x+3). Hence 3x−3≤2x+6, so x≤9.
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