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100g ice−10°C becomes water0°C. cice=2.1kJ/(kgK), Lf=334kJ/kg. Heat absorbed?

A31.3kJ
B35.5kJ
C33.4kJ
D2.1kJ
Answer & Solution
Correct answer: B. 35.5kJ
Warming the ice takes 2.1kJ and melting it takes 33.4kJ, totalling 35.5kJ.
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