allerySame power, no loss: ice0°C melts in8t; equal water mass warms10K in t. Lf/cwater?
A10K
B8K
C800K
D80K
Answer & Solution
Correct answer: D. 80K
Equal heater power gives mLf=8mc×10K, hence Lf/c=80K.
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Related questions
Match each everyday calorimetric effect with its physics explanation:Match each thermal mixing concept with its rule:Match each substance with its notable calorimetric property:Match each thermal capacity term with its definition and formula:Equal water masses80°C,20°C mix in a cup20°C of the same heat capacity as one mass. No losWater0°C freezes to warm20g ice−10→0°C. cice=2.1J/(gK), Lf=336J/g. No other heat. Mass fro50g ice0°C receives4.2kJ from cooling water. Lf=336J/g. No other heat. Ice remaining?100g water40°C+20g ice0°C. cwater=4.2J/(gK), Lf=336J/g. No loss; cup negligible. Final T?