Water0°C freezes to warm20g ice−10→0°C. cice=2.1J/(gK), Lf=336J/g. No other heat. Mass frozen?
A0g
B1.25g
C12.5g
D20g
Answer & Solution
Correct answer: B. 1.25g
Warming the ice to 0°C needs 420J, supplied by freezing 420/336=1.25g of water.
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