Start learning →

Water0°C freezes to warm20g ice−10→0°C. cice=2.1J/(gK), Lf=336J/g. No other heat. Mass frozen?

A0g
B1.25g
C12.5g
D20g
Answer & Solution
Correct answer: B. 1.25g
Warming the ice to 0°C needs 420J, supplied by freezing 420/336=1.25g of water.
Practise this question with Quill — ICSE Class 10 →

Keep practising Heat: calorimetry, specific heat capacity and latent heat

Browse all Heat: calorimetry, specific heat capacity and latent heat questions for ICSE Class 10, or explore more Physics topics.

Start a Heat: calorimetry, specific heat capacity and latent heat lesson →