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A 0.25 kg liquid cools by 8 K and releases 6 kJ. Its c is:

A300 J kg−1 K−1
B3000 J kg−1 K−1
C750 J kg−1 K−1
D6000 J kg−1 K−1
Answer & Solution
Correct answer: B. 3000 J kg−1 K−1
c = Q/(mΔT) = 6000/(0.25 × 8) = 3000 J kg−1 K−1.
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