If 600 kJ vaporizes 2 kg of a liquid, its specific latent heat is:
A300 kJ kg−1
B1200 kJ kg−1
C120 kJ kg−1
D600 kJ kg−1
Answer & Solution
Correct answer: A. 300 kJ kg−1
Dividing 600 kJ by 2 kg gives 300 kJ kg−1.
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