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The integral of (3x^2 + 2x) dx is

Ax^3 + x^2 + C
Bx^3 + 2x^2 + C
C3x^3 + x^2 + C
D6x + 2 + C
Answer & Solution
Correct answer: A. x^3 + x^2 + C
Integrating term by term gives x^3 from 3x^2 and x^2 from 2x.
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