Home › TS EAMCET › Mathematics › Trigonometry: Trigonometric Ratios upto Transformations › The product of sin(kπ/6) for k = 1, 2, 3, 4, 5 e…
The product of sin(kπ/6) for k = 1, 2, 3, 4, 5 equals:
A1/32
B3/16
C6/32
D1/8
Answer & Solution
Correct answer: B. 3/16
The product of sin(kπ/n) for k = 1 to n−1 equals n/2^(n−1); for n = 6 this is 6/32 = 3/16.
Related questions
If sin θ + cos θ = 1, and 0 ≤ θ ≤ π/2, which pair of values of θ is possible?Evaluate sin 105° + sin 15° using the sum-to-product rule.Simplify sin 50° cos 20° - cos 50° sin 20°.What is the value of sin 75° cos 15° + cos 75° sin 15°?Which expression equals 2 sin²(θ) for every θ, by the power-reduction idea?Which expression equals 3 sin θ - 4 sin³θ for every θ?A ladder makes tan θ = 3/4 with the ground, θ acute. What is sec θ?If sin θ = 5/13 and θ is acute, what is the value of cos θ?