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Which expression equals 2 sin²(θ) for every θ, by the power-reduction idea?
A1 + cos 2θ
B1 - cos 2θ
Ccos 2θ - 1
Dsin 2θ
Answer & Solution
Correct answer: B. 1 - cos 2θ
From cos 2θ = 1 - 2sin²θ we get 2sin²θ = 1 - cos 2θ.
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