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If sin θ + cos θ = 1, and 0 ≤ θ ≤ π/2, which pair of values of θ is possible?
Aπ/6 and π/3
Bπ/4 only
C0 and π/2
Dπ/3 and π/2
Answer & Solution
Correct answer: C. 0 and π/2
Squaring gives 1 + sin 2θ = 1, so sin 2θ = 0, which gives θ = 0 or θ = π/2 in the interval.
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