Home › TS EAMCET › Mathematics › Trigonometry: Trigonometric Ratios upto Transformations › The product 2 sin 3x cos x can be written as:
The product 2 sin 3x cos x can be written as:
Acos 4x + cos 2x
Bsin 3x + sin x
Csin 4x + sin 2x
Dsin 4x − sin 2x
Answer & Solution
Correct answer: C. sin 4x + sin 2x
2 sin A cos B = sin(A + B) + sin(A − B), which gives sin 4x + sin 2x.
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