Home › AP EAPCET (Engineering) › Mathematics › Algebra: Partial Fractions › A partial sum of the first N terms of 1/(n(n+1))…
A partial sum of the first N terms of 1/(n(n+1)) equals
A1/(N+1)
B(N+1)/N
CN/(N+2)
DN/(N+1)
Answer & Solution
Correct answer: D. N/(N+1)
Telescoping 1/n - 1/(n+1) leaves 1 - 1/(N+1) = N/(N+1).
Related questions
How many constants split 1/((x-1)^2 (x+2))?Which pair of fractions adds up to (2x+1)/(x^2+x-2)?x/((x+1)(x+2)) breaks into which pair of fractions?Real-variable integral calculus uses partial fractions to find antiderivatives ofWhich fraction needs long division before it can be decomposed?The first derivative at x = a of (x-a)^2 p(x) equalsSplitting a fraction with coprime denominator factors relies on which identity?Equating coefficients to find the constants is a variant of the method of