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The first derivative at x = a of (x-a)^2 p(x) equals
A0
Bp'(a)
Cp(a)
D2p(a)
Answer & Solution
Correct answer: A. 0
The derivative is 2(x-a)p(x) + (x-a)^2 p'(x), and both terms vanish at x = a.
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