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Splitting a fraction with coprime denominator factors relies on which identity?
ADe Moivre's theorem
BEuler's identity
CBézout's identity
DVieta's formulas
Answer & Solution
Correct answer: C. Bézout's identity
Bezout's identity gives polynomials C and D with C G1 + D G2 = 1 for coprime G1 and G2.
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