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Which difference of simple fractions equals 3/((x+1)(x+4))?
A1/(x+4) - 1/(x+1)
B1/(x+1) - 1/(x+4)
C1/(x+1) + 1/(x+4)
D3/(x+1) - 3/(x+4)
Answer & Solution
Correct answer: B. 1/(x+1) - 1/(x+4)
The difference of the denominators is 3, so 1/(x+1) - 1/(x+4) = 3/((x+1)(x+4)).
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