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Find the value of the integral of 1/((x-1)(x-2)) dx.
Aln|(x-1)/(x-2)| + C
B-ln|(x-2)/(x-1)| + C
Cln|(x-1)(x-2)| + C
Dln|(x-2)/(x-1)| + C
Answer & Solution
Correct answer: D. ln|(x-2)/(x-1)| + C
The fraction equals 1/(x-2) - 1/(x-1), so the integral is ln|x-2| - ln|x-1|.
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