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Integrating 1/(x(x+1)) with respect to x gives
Aln|x/(x+1)| + C
B-ln|x(x+1)| + C
Cln|x(x+1)| + C
Dln|(x+1)/x| + C
Answer & Solution
Correct answer: A. ln|x/(x+1)| + C
Splitting into 1/x - 1/(x+1) and integrating gives ln|x| - ln|x+1|.
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