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Solve tan x = −1/√3 completely.
Ax = nπ + π/6, n ∈ Z
Bx = nπ ± π/6, n ∈ Z
Cx = nπ + π/3, n ∈ Z
Dx = nπ − π/6, n ∈ Z
Answer & Solution
Correct answer: D. x = nπ − π/6, n ∈ Z
tan(−π/6) = −1/√3, so x = nπ + α gives x = nπ − π/6.
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