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The multiple-angle formula for sin 3A is
A3 sin A + 4 sin³A
B4 sin A − 3 sin³A
C3 sin A − 4 sin³A
D3 cos A − 4 cos³A
Answer & Solution
Correct answer: C. 3 sin A − 4 sin³A
Expanding sin(2A + A) and using sin²A + cos²A = 1 gives 3 sin A − 4 sin³A.
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