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The sum sin C + sin D equals
A2 cos((C+D)/2) cos((C−D)/2)
B2 sin((C+D)/2) cos((C−D)/2)
C2 sin((C+D)/2) sin((C−D)/2)
D2 cos((C+D)/2) sin((C−D)/2)
Answer & Solution
Correct answer: B. 2 sin((C+D)/2) cos((C−D)/2)
Setting C = A+B and D = A−B in the product formula gives 2 sin of the half-sum times cos of the half-difference.
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