Home › TS EAPCET (Engineering) › Mathematics › Trigonometric Functions › The least positive root of the equation sin 2x =…
The least positive root of the equation sin 2x = sin x is
Aπ/2
Bπ/6
Cπ/3
Dπ
Answer & Solution
Correct answer: C. π/3
sin x (2 cos x - 1) = 0, so the smallest positive root comes from cos x = 1/2, namely x = π/3.
Related questions
Inside (0, π/2), the angle where tan x equals its own reciprocal isAdding every root of 2 sin x cos x = sin x on [0, π] givesBetween 0 and 2π inclusive, how many angles satisfy sin 2x = 1?Solving sin x = sin α completely, with n an integer, givesTangent takes positive values in which pair of quadrants?A point has sine 3/5 and sits in the second quadrant; its cosine isHalving the angle inside a cosine stretches its repetition length toThe sine wave of 3x repeats after how much increase in x?