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Solving sin x = sin α completely, with n an integer, gives
Ax = nπ + (-1)^n α
Bx = nπ - (-1)^n α
Cx = 2nπ + (-1)^n α
Dx = nπ + (-1)^(n+1) α
Answer & Solution
Correct answer: A. x = nπ + (-1)^n α
Sine repeats with period 2π and also satisfies sin(π - α) = sin α, which combine into nπ + (-1)^n α.
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