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Adding every root of 2 sin x cos x = sin x on [0, π] gives
A4π/3
Bπ
C5π/3
Dπ/3
Answer & Solution
Correct answer: A. 4π/3
sin x (2 cos x - 1) = 0 gives x = 0, π/3 and π, whose sum is 4π/3.
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