The auxiliary equation whose roots are the slopes of ax² + 2hxy + by² = 0 is
Aam² + 2hm + b = 0
Bbm² + 2hm + a = 0
Cbm² - 2hm + a = 0
Dam² + hm + b = 0
Answer & Solution
Correct answer: B. bm² + 2hm + a = 0
Substituting y = mx and dividing by x² gives b m² + 2h m + a = 0.
Keep practising Pair of Straight Lines
Browse all Pair of Straight Lines questions for MHT-CET, or explore more Mathematics topics.
Related questions
If m1 and m2 are slopes of the lines of ax² + 2hxy + by² = 0, then m1m2 equalsAn equation that represents two lines at once is called what?What does the equation uv = 0 represent, where u = 0 and v = 0 are lines?Find the bisector pair for the lines 3x² + 10xy + 3y² = 0.What is the relation between the two angle bisectors of a pair of lines through the originWhat is the joint equation of the bisectors of the angles between ax² + 2hxy + by² = 0?Where do the lines in x² - 6xy + 5y² + 10x - 14y + 9 = 0 intersect?Find tan θ for the acute angle between the pair x² - 6xy + 5y² + 10x - 14y + 9 = 0.