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What is the joint equation of the bisectors of the angles between ax² + 2hxy + by² = 0?

Ahx² + (a - b)xy - hy² = 0
Bhx² - (a - b)xy - hy² = 0
Chx² - (a + b)xy + hy² = 0
Dax² - 2hxy + by² = 0
Answer & Solution
Correct answer: B. hx² - (a - b)xy - hy² = 0
The bisector pair is hx² - (a - b)xy - hy² = 0.
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