alleryStart learning →Find the bisector pair for the lines 3x² + 10xy + 3y² = 0.
Ax² + y² = 0
Bx² - xy = 0
Cx² - y² = 0
Dx² + 2xy - y² = 0
Answer & Solution
Correct answer: C. x² - y² = 0
Here a = b = 3 and h = 5, so the pair is 5x² - 0·xy - 5y² = 0, i.e. x² - y² = 0.
Keep practising Pair of Straight Lines
Browse all Pair of Straight Lines questions for MHT-CET, or explore more Mathematics topics.
Related questions
If m1 and m2 are slopes of the lines of ax² + 2hxy + by² = 0, then m1m2 equalsAn equation that represents two lines at once is called what?What does the equation uv = 0 represent, where u = 0 and v = 0 are lines?What is the relation between the two angle bisectors of a pair of lines through the originWhat is the joint equation of the bisectors of the angles between ax² + 2hxy + by² = 0?Where do the lines in x² - 6xy + 5y² + 10x - 14y + 9 = 0 intersect?Find tan θ for the acute angle between the pair x² - 6xy + 5y² + 10x - 14y + 9 = 0.For x² - 6xy + 5y² + 10x - 14y + 9 = 0, what is abc + 2fgh - af² - bg² - ch²?