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Which equation gives two mutually perpendicular lines?

Ax² + 4xy + 4y² = 0
B3x² - 4xy - 3y² = 0
C2x² + xy + y² = 0
Dx² - 6xy + 5y² = 0
Answer & Solution
Correct answer: B. 3x² - 4xy - 3y² = 0
Only 3x² - 4xy - 3y² has coefficients of x² and y² summing to zero.
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