alleryStart learning →Writing tan(2θ + θ) in terms of tanθ gives
A(3 tanθ + tan³θ) / (1 + 3 tan²θ)
B(3 tanθ − tan³θ) / (1 + 3 tan²θ)
C(tan³θ − 3 tanθ) / (1 − 3 tan²θ)
D(3 tanθ − tan³θ) / (1 − 3 tan²θ)
Answer & Solution
Correct answer: D. (3 tanθ − tan³θ) / (1 − 3 tan²θ)
Expanding tan(2θ + θ) gives (3tanθ − tan³θ)/(1 − 3tan²θ).
Keep practising Trigonometry - II
Browse all Trigonometry - II questions for MHT-CET, or explore more Mathematics topics.
Related questions
If sinθ = 1/2 with θ acute, what is the value of sin 3θ − 3 sinθ?Which of these is the correct value of sin(3π/2 − θ)?In the second quadrant, sin(π − θ) is equal toUsing a period of 180°, tan 840° reduces toRemoving two full turns, cos 930° reduces toReducing 495° to a first-turn angle, sin 495° equalsFor the angles of any triangle, the sum sin2A + sin2B + sin2C isThe triangle identity for squares of sines gives sin²A + sin²B + sin²C =