alleryStart learning →For the angles of any triangle, the sum sin2A + sin2B + sin2C is
A4 cosA cosB cosC
B4 sinA sinB sinC
C2 sinA sinB sinC
D1 + 4 cosA cosB cosC
Answer & Solution
Correct answer: B. 4 sinA sinB sinC
For A + B + C = π the standard result is sin2A + sin2B + sin2C = 4 sinA sinB sinC.
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